Solved QUESTION 7 What volume of 12.0 M HCl is required to
What Volume Of 12.0 M Hcl Is Required To. 12 m = 12 moles hcl per 1 liter of solution.so 12 moles/ 1 liter = 3 moles/ x liters. The density of your hcl is 1.179.
Solved QUESTION 7 What volume of 12.0 M HCl is required to
What volume of 12.0 m hcl is required to make 75.0 ml of 3.50. Web what volume of 12.0 m hci is required to make 75.0 ml of 3.50 m hcl? 12 m = 12 moles hcl per 1 liter of solution.so 12 moles/ 1 liter = 3 moles/ x liters. Ml 0.560 ml 21.9 ml 257 ml this problem has been solved! = volume of concentrated hcl solution = ? Web solution for what volume of 12.0 m hcl is required to make 75.0 ml of 3.50 m hcl? None of the above answered:. The density of your hcl is 1.179. Web 75ml=0.075lmolarity=moles/litersmoles=0.075(3.50)=0.2625since the number of moles never changes,we know there are 0.2625moles (or 0.26) in the 12m. You'll get a detailed solution from a.
Mass of hcl in one molar solution which is the molar mass is 36.5. = molarity of hcl solution =. Web solution for what volume of 12.0 m hcl is required to make 75.0 ml of 3.50 m hcl? What volume of 12.0 m hcl is required to prepare 16.0 l of 0.250 m hydrochloric acid? We all know that density = mass/volume. You'll get a detailed solution from a. = volume of concentrated hcl solution = ? What volume of 12.0 m hcl is required to make 75.0 ml of 3.50. Web v₁ = 21.9 ml (following scientific notation, round to the nearest tenths) therefore, the volume of the 12.0 m hcl required is 21.9 ml. Web since you need $\pu{262.5 mmol}$, and the $\pu{12 m }$ solution has $\pu{12 mmol}$ per $\pu{ml}$, then you need $\pu{262.5mmol}\div \pu{12m} = \pu{21.875 ml}$ of $\pu{12 m. Web what volume of 12.0 m hcl is required to make 75.0 ml of 3.50 m hcl?
